To determine how the acceleration changes with different net forces acting on the object, we can use Newton's second law of motion, which states:
\[ F_{\text{net}} = ma \]
Where:
- \( F_{\text{net}} \) is the net force,
- \( m \) is the mass,
- \( a \) is the acceleration.
First, let's calculate the acceleration with the original net force of 0.8 N:
Given:
- \( F_{\text{net}} = 0.8 , \text{N} \)
- \( m = 1.5 , \text{kg} \)
Using the formula, we can solve for acceleration \( a \):
\[ a = \frac{F_{\text{net}}}{m} = \frac{0.8 , \text{N}}{1.5 , \text{kg}} = \frac{0.8}{1.5} \approx 0.533 , \text{m/s}^2 \]
Now, let's calculate the acceleration with the new net force of 0.2 N:
Given:
- \( F_{\text{net}} = 0.2 , \text{N} \)
- \( m = 1.5 , \text{kg} \)
Again using the formula, we can solve for the new acceleration \( a \):
\[ a = \frac{F_{\text{net}}}{m} = \frac{0.2 , \text{N}}{1.5 , \text{kg}} = \frac{0.2}{1.5} \approx 0.133 , \text{m/s}^2 \]
Now we can compare the two accelerations. The initial acceleration was approximately 0.533 m/s² and the new acceleration is approximately 0.133 m/s², which is indeed a quarter of the original acceleration:
\[ 0.133 , \text{m/s}^2 \approx \frac{0.533 , \text{m/s}^2}{4} \]
Therefore, the correct response is:
The acceleration decreases to a quarter of its original value, or about 0.13 m/s².