Asked by ~christina~

how would I draw this compound?

<b>2-bromo-6-chloro-4,4-dimethylheptane</b>

I've tried it again and again but I can't seem to get the Cl on the 6th carbon while still having a 6 carbon chain of heptane

I drew it
so that

it was
CH3 CBr CH2 CCH3CH3 CH2 Cl

I just can't figure it out..can someone help me?

Thanks
Answered by bobpursley
heptane is a seven chain...
Answered by ~christina~
I know but the problem is when I have to fit the Cl on the 6th carbon...but I can't seem to do that without putting in too much carbons.

Answered by DrBob222
Take your structure in the first post and simply add CH3 at the end (substitute CH3 for one of the Hs on the CH2Cl. I THINK your problem is you are counting one of the dimethyl groups as one of the carbons in the chain for heptane.
<b>
CH3
|
CHBr
|
CH2
|
C(CH3)2
|
CH2
|
CHCl
|
CH3
</b> Check out my try and see if it has any flaws.
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