Question
You toss a penny, nickel, dime, and quarter. What is the probability of all four landing on tails?
(1 point)
Responses
12
1 2
14
1 4
18
1 8
116
(1 point)
Responses
12
1 2
14
1 4
18
1 8
116
Answers
GPT-4o mini
To find the probability of all four coins landing on tails, we can consider that each coin has two possible outcomes: heads (H) or tails (T).
The probability of landing on tails for each coin is \( \frac{1}{2} \).
Since the tosses of the coins are independent events, we can multiply the probabilities:
\[
P(\text{all tails}) = P(\text{tails for penny}) \times P(\text{tails for nickel}) \times P(\text{tails for dime}) \times P(\text{tails for quarter})
\]
\[
= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}
\]
\[
= \left(\frac{1}{2}\right)^4 = \frac{1}{16}
\]
Thus, the probability of all four coins landing on tails is \( \frac{1}{16} \).
The correct answer is:
116
The probability of landing on tails for each coin is \( \frac{1}{2} \).
Since the tosses of the coins are independent events, we can multiply the probabilities:
\[
P(\text{all tails}) = P(\text{tails for penny}) \times P(\text{tails for nickel}) \times P(\text{tails for dime}) \times P(\text{tails for quarter})
\]
\[
= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}
\]
\[
= \left(\frac{1}{2}\right)^4 = \frac{1}{16}
\]
Thus, the probability of all four coins landing on tails is \( \frac{1}{16} \).
The correct answer is:
116