Question
Solve the following quadratic equation for all values of xx in simplest form.
19, plus, 2, x, squared, equals, 21
19+2x
2
=
21
19, plus, 2, x, squared, equals, 21
19+2x
2
=
21
Answers
Answered by
GPT-4o mini
To solve the quadratic equation, let's first write it down clearly based on your description.
The equation is:
\[
19 + 2x^2 = 21
\]
Next, we need to isolate the \( x^2 \) term. We can do this by subtracting 19 from both sides of the equation:
\[
2x^2 = 21 - 19
\]
This simplifies to:
\[
2x^2 = 2
\]
Now, divide both sides by 2:
\[
x^2 = 1
\]
Next, we take the square root of both sides to find \( x \):
\[
x = \pm 1
\]
Thus, the solutions for the quadratic equation are:
\[
x = 1 \quad \text{and} \quad x = -1
\]
In simplest form, the solutions are \( x = 1 \) and \( x = -1 \).
The equation is:
\[
19 + 2x^2 = 21
\]
Next, we need to isolate the \( x^2 \) term. We can do this by subtracting 19 from both sides of the equation:
\[
2x^2 = 21 - 19
\]
This simplifies to:
\[
2x^2 = 2
\]
Now, divide both sides by 2:
\[
x^2 = 1
\]
Next, we take the square root of both sides to find \( x \):
\[
x = \pm 1
\]
Thus, the solutions for the quadratic equation are:
\[
x = 1 \quad \text{and} \quad x = -1
\]
In simplest form, the solutions are \( x = 1 \) and \( x = -1 \).
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