To find the vertex of the quadratic function \( h = -6t^2 - 24t + 20 \), we can use the vertex formula for a parabola, which is given by \( t = -\frac{b}{2a} \), where \( a \) and \( b \) are the coefficients from the standard form \( at^2 + bt + c \).
In this case:
- \( a = -6 \)
- \( b = -24 \)
Now, we can find the \( t \)-coordinate of the vertex:
\[ t = -\frac{b}{2a} = -\frac{-24}{2 \cdot -6} = \frac{24}{-12} = -2 \]
Now that we have \( t = -2 \), we can find the corresponding \( h \)-coordinate by plugging \( t \) back into the original function:
\[ h = -6(-2)^2 - 24(-2) + 20 \]
Calculating step-by-step:
- \( (-2)^2 = 4 \)
- \( -6 \cdot 4 = -24 \)
- \( -24 \cdot -2 = 48 \)
- Now substitute: \[ h = -24 + 48 + 20 = 44 \]
So the vertex is at the point \( (-2, 44) \).
The correct ordered pair that represents the vertex is:
\[ \boxed{(-2, 44)} \]