To represent the situation with equations based on the information provided, we need to analyze the ticket sales for each group:
-
First Group:
- Purchases 2 child tickets (c), 1 adult ticket (a), and spends $67.
- This can be represented as: \[ 2c + 1a + 0s = 67 \quad \text{(Equation 1)} \]
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Second Group:
- Purchases 3 child tickets, 1 adult ticket, and 1 senior ticket (s) for a total of $169.
- This can be represented as: \[ 3c + 1a + 1s = 169 \quad \text{(Equation 2)} \]
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Third Group:
- Purchases 1 child ticket, 2 adult tickets, and 2 senior tickets for a total of $172.
- This can be represented as: \[ 1c + 2a + 2s = 172 \quad \text{(Equation 3)} \]
Now, if we summarize the correct equations from the options provided:
- \( 2c + a = 67 \) (or \(2c + 1a + 0s = 67\))
- \( 3c + a + s = 169 \)
- \( c + 2a + 2s = 172 \)
From the list of responses provided, these match:
- \( 2c + a = 67 \)
- \( 3c + a + s = 169 \)
- \( c + 2a + 2s = 172 \)
Therefore, the three equations that represent the situation are:
- \( 2c + a = 67 \) (First Group)
- \( 3c + a + s = 169 \) (Second Group)
- \( c + 2a + 2s = 172 \) (Third Group)