To find the equation of the line that passes through the point (2, -3) with a slope of -3, we can use the point-slope form of a linear equation, which is given by:
\[ y - y_1 = m(x - x_1) \]
Where:
- \((x_1, y_1)\) is the point the line passes through (2, -3),
- \(m\) is the slope (-3).
Substituting the values into the formula:
\[ y - (-3) = -3(x - 2) \]
This simplifies to:
\[ y + 3 = -3(x - 2) \]
Distributing the \(-3\):
\[ y + 3 = -3x + 6 \]
Now, subtracting 3 from both sides:
\[ y = -3x + 3 \]
So the equation of the line in slope-intercept form (y = mx + b) is:
\[ \boxed{y = -3x + 3} \]