Question

The lesson asked you to create a new PythonAnywhere file with the following code:

decimalNum = int(input("Please enter a decimal number: "))
binaryList = []
while decimalNum > 0:
decimalNum = decimalNum / 2
remainder = decimalNum % 2
binaryList.append(remainder)
print(binaryList)

What is the result of running this code and entering 24 as your number?

(1 point)
Responses

[0, 0, 0, 1, 1]
[0, 0, 0, 1, 1] - incorrect

A huge list of decimal values.
A huge list of decimal values. - no response given

0011 0000
0011 0000 - no response given

24

Answer 1

The code provided contains a few logical issues that will affect its output. Let's go through it step by step to analyze what will happen when you input the decimal number 24.

1. The `decimalNum` variable starts with the value `24`.
2. The `while` loop checks if `decimalNum > 0`. Since `24 > 0`, we enter the loop.
3. Inside the loop, the first operation is `decimalNum = decimalNum / 2`. This performs a floating-point division, so `decimalNum` becomes `12.0` after the first iteration.
4. Next, the remainder calculation `remainder = decimalNum % 2` will also use the new `decimalNum` value, which is a float (`12.0`). This will evaluate to `0.0` because `12.0` is even.
5. The value `0.0` then gets appended to `binaryList`.
6. The loop continues, recalculating `decimalNum` each time using floating-point division, and calculating the remainder with the same method.

Following this process for the initial value `24`, you will find that:

- First iteration: `decimalNum = 12.0`, remainder `0.0`
- Second iteration: `decimalNum = 6.0`, remainder `0.0`
- Third iteration: `decimalNum = 3.0`, remainder `1.0`
- Fourth iteration: `decimalNum = 1.5`, remainder `0.5`
- Fifth iteration: `decimalNum = 0.75`, remainder `0.75`
- Sixth iteration: `decimalNum = 0.375`, remainder `0.375`
- And so on...

Since the code keeps dividing by 2, eventually `decimalNum` will become less than 1, exiting the loop.

The output you would see from this code with the input `24` is an accumulating list of floating point remainders, including `0.0, 0.0, 1.0, 0.5, ...` until the loop stops.

Thus, to summarize, the result of running this code with the input `24` will be a list containing mostly `0.0`, `1.0`, and some other small floating-point numbers, and will not appear in any of the provided choices.

In conclusion, none of the provided responses are correct based on the observation of the code's behavior. The actual output would be a list of those floating point values.