Question
Question 1
A)Correctly label the sides of the triangle shown below(3 points)
Drop target 1
Drop target 2
Drop target 3
B)For the triangle shown above, RP¯¯¯¯¯¯¯¯ =24, and DR¯¯¯¯¯¯¯¯=7
, which of the following the correct way to set up the problem to find DP?(2 points)
Responses
x2+72=242
x squared plus 7 squared is equal to 24 squared
x2+242=72
x squared plus 24 squared is equal to 7 squared
24+7=x
24 plus 7 is equal to x
242+72=x2
24 squared plus 7 squared is equal to x squared
C)What is DP? Round your answer to the nearest tenth if necessary(2 points)
DP =
$$
Question 2
A)For the triangle shown below, correctly label the sides(3 points)
Drop target 1
Drop target 2
Drop target 3
B)If CE = 29 and AC = 20, which of the following equations can be used to find AE?(2 points)
Responses
202+292=x2
20 squared plus 29 squared is equal to x squared
202+x2=292
20 squared plus x squared is equal to 29 squared
20+x=29
20 plus x is equal to 29
20+29=x
20 plus 29 is equal to x
C)Using the information given above, find AE. Round to the nearest tenth if necessary.(2 points)
AE =
$$
Question 3
A)
For the triangle pictured above, which side is the hypotenuse?
(1 point)
Responses
We do not have enough information in the given information.
We do not have enough information in the given information.
The side labeled 11.9 km
The side labeled 11.9 km
The side labled 14.7 km
The side labled 14.7 km
The side labeled x
The side labeled x
B)What is the value of x? Round to the nearest tenth if necessary. (1 point)
Responses
18.9 km
18.9 km
74.5 km
74.5 km
2.8 km
2.8 km
8.6 km
8.6 km
Question 4
A)
If YS = 6.3 km and YL = 15.4 km, find the length of LS. Round your answer to the nearest tenth if necessary. You must show ALL work in order to receive full credit. You may type your work or use the button to insert a picture of your work.
A good example of how work should be shown is
(4 points)
0 / 10000 Word Limit
Question 5
A)
If JE = 4.8 and EW = 28.6, find the length of JW. Round your answer to the nearest tenth if necessary.
You must show ALL work in order to receive full credit. You may type your work or use the button to insert a picture of your work.
A good example of how work should be shown is
(4 points)
0 / 10000 Word Limit
Question 6
A)
If one of the legs of a triangle measures 10 cm and the hypotenuse measures 50.5 cm, find the length of the other leg? Round your answer to the nearest tenth if necessary.
You must show ALL work in order to receive full credit. You may type your work or use the button to insert a picture of your work.
A good example of how work should be shown is
(4 points)
0 / 10000 Word Limit
Question 7
Help video for Pythagorean Theorem
Video Player
A)Correctly label the sides of the triangle shown below(3 points)
Drop target 1
Drop target 2
Drop target 3
B)For the triangle shown above, RP¯¯¯¯¯¯¯¯ =24, and DR¯¯¯¯¯¯¯¯=7
, which of the following the correct way to set up the problem to find DP?(2 points)
Responses
x2+72=242
x squared plus 7 squared is equal to 24 squared
x2+242=72
x squared plus 24 squared is equal to 7 squared
24+7=x
24 plus 7 is equal to x
242+72=x2
24 squared plus 7 squared is equal to x squared
C)What is DP? Round your answer to the nearest tenth if necessary(2 points)
DP =
$$
Question 2
A)For the triangle shown below, correctly label the sides(3 points)
Drop target 1
Drop target 2
Drop target 3
B)If CE = 29 and AC = 20, which of the following equations can be used to find AE?(2 points)
Responses
202+292=x2
20 squared plus 29 squared is equal to x squared
202+x2=292
20 squared plus x squared is equal to 29 squared
20+x=29
20 plus x is equal to 29
20+29=x
20 plus 29 is equal to x
C)Using the information given above, find AE. Round to the nearest tenth if necessary.(2 points)
AE =
$$
Question 3
A)
For the triangle pictured above, which side is the hypotenuse?
(1 point)
Responses
We do not have enough information in the given information.
We do not have enough information in the given information.
The side labeled 11.9 km
The side labeled 11.9 km
The side labled 14.7 km
The side labled 14.7 km
The side labeled x
The side labeled x
B)What is the value of x? Round to the nearest tenth if necessary. (1 point)
Responses
18.9 km
18.9 km
74.5 km
74.5 km
2.8 km
2.8 km
8.6 km
8.6 km
Question 4
A)
If YS = 6.3 km and YL = 15.4 km, find the length of LS. Round your answer to the nearest tenth if necessary. You must show ALL work in order to receive full credit. You may type your work or use the button to insert a picture of your work.
A good example of how work should be shown is
(4 points)
0 / 10000 Word Limit
Question 5
A)
If JE = 4.8 and EW = 28.6, find the length of JW. Round your answer to the nearest tenth if necessary.
You must show ALL work in order to receive full credit. You may type your work or use the button to insert a picture of your work.
A good example of how work should be shown is
(4 points)
0 / 10000 Word Limit
Question 6
A)
If one of the legs of a triangle measures 10 cm and the hypotenuse measures 50.5 cm, find the length of the other leg? Round your answer to the nearest tenth if necessary.
You must show ALL work in order to receive full credit. You may type your work or use the button to insert a picture of your work.
A good example of how work should be shown is
(4 points)
0 / 10000 Word Limit
Question 7
Help video for Pythagorean Theorem
Video Player
Answers
GPT-4o mini
### Question 1
#### A) Correctly label the sides of the triangle.
- **Drop target 1**: RP
- **Drop target 2**: DR
- **Drop target 3**: DP
#### B) Correct way to set up the problem to find DP:
The correct response is:
**\(x^2 + 7^2 = 24^2\)**
(20 squared plus 7 squared is equal to 24 squared)
#### C) Find DP.
Using the Pythagorean theorem:
\(x^2 + 7^2 = 24^2\)
\(x^2 + 49 = 576\)
\(x^2 = 576 - 49\)
\(x^2 = 527\)
\(x = \sqrt{527} \approx 22.9\)
**DP ≈ 22.9**
---
### Question 2
#### A) Correctly label the sides.
- **Drop target 1**: AC
- **Drop target 2**: CE
- **Drop target 3**: AE
#### B) Equation to find AE:
The correct response is:
**\(20^2 + x^2 = 29^2\)**
(20 squared plus x squared is equal to 29 squared)
#### C) Find AE.
Using the equation:
\(20^2 + x^2 = 29^2\)
\(400 + x^2 = 841\)
\(x^2 = 841 - 400\)
\(x^2 = 441\)
\(x = \sqrt{441} = 21\)
**AE = 21.0**
---
### Question 3
#### A) Which side is the hypotenuse?
The response is:
**The side labeled 14.7 km.**
(Always the longest side in a right triangle)
#### B) What is the value of x?
Using the Pythagorean theorem:
Let the sides be 11.9 and 14.7 as the legs.
Then:
\(11.9^2 + x^2 = 14.7^2\)
Calculate it:
\(141.61 + x^2 = 216.09\)
\(x^2 = 216.09 - 141.61\)
\(x^2 = 74.48\)
\(x ≈ 8.6\)
**x ≈ 8.6 km**
---
### Question 4
#### Find the length of LS:
Using the Pythagorean theorem:
- YS = 6.3 km (one leg)
- YL = 15.4 km (the other leg)
Use:
\(LS^2 + YS^2 = YL^2\)
Let LS = x:
\(x^2 + 6.3^2 = 15.4^2\)
Calculate:
\(x^2 + 39.69 = 237.16\)
\(x^2 = 237.16 - 39.69\)
\(x^2 = 197.47\)
\(x ≈ \sqrt{197.47} ≈ 14.0\)
**LS ≈ 14.0 km**
---
### Question 5
#### Find the length of JW:
Using the Pythagorean theorem:
- JE = 4.8 (one leg)
- EW = 28.6 (the other leg)
Use:
\(JW^2 + JE^2 = EW^2\)
Let JW = x:
\(x^2 + 4.8^2 = 28.6^2\)
Calculate:
\(x^2 + 23.04 = 817.96\)
\(x^2 = 817.96 - 23.04\)
\(x^2 = 794.92\)
\(x ≈ \sqrt{794.92} ≈ 28.2\)
**JW ≈ 28.2**
---
### Question 6
#### Find the length of the other leg:
Using the Pythagorean theorem:
- One leg = 10 cm
- Hypotenuse = 50.5 cm
Let the unknown leg = x:
\(x^2 + 10^2 = 50.5^2\)
Calculate:
\(x^2 + 100 = 2550.25\)
\(x^2 = 2550.25 - 100\)
\(x^2 = 2450.25\)
\(x ≈ \sqrt{2450.25} ≈ 49.5\)
**The other leg ≈ 49.5 cm**
---
### Question 7
For any video-related question, ensure to check the provided materials or links elsewhere, as I can’t provide or display video content.
Feel free to ask if you need further assistance on specific parts!
#### A) Correctly label the sides of the triangle.
- **Drop target 1**: RP
- **Drop target 2**: DR
- **Drop target 3**: DP
#### B) Correct way to set up the problem to find DP:
The correct response is:
**\(x^2 + 7^2 = 24^2\)**
(20 squared plus 7 squared is equal to 24 squared)
#### C) Find DP.
Using the Pythagorean theorem:
\(x^2 + 7^2 = 24^2\)
\(x^2 + 49 = 576\)
\(x^2 = 576 - 49\)
\(x^2 = 527\)
\(x = \sqrt{527} \approx 22.9\)
**DP ≈ 22.9**
---
### Question 2
#### A) Correctly label the sides.
- **Drop target 1**: AC
- **Drop target 2**: CE
- **Drop target 3**: AE
#### B) Equation to find AE:
The correct response is:
**\(20^2 + x^2 = 29^2\)**
(20 squared plus x squared is equal to 29 squared)
#### C) Find AE.
Using the equation:
\(20^2 + x^2 = 29^2\)
\(400 + x^2 = 841\)
\(x^2 = 841 - 400\)
\(x^2 = 441\)
\(x = \sqrt{441} = 21\)
**AE = 21.0**
---
### Question 3
#### A) Which side is the hypotenuse?
The response is:
**The side labeled 14.7 km.**
(Always the longest side in a right triangle)
#### B) What is the value of x?
Using the Pythagorean theorem:
Let the sides be 11.9 and 14.7 as the legs.
Then:
\(11.9^2 + x^2 = 14.7^2\)
Calculate it:
\(141.61 + x^2 = 216.09\)
\(x^2 = 216.09 - 141.61\)
\(x^2 = 74.48\)
\(x ≈ 8.6\)
**x ≈ 8.6 km**
---
### Question 4
#### Find the length of LS:
Using the Pythagorean theorem:
- YS = 6.3 km (one leg)
- YL = 15.4 km (the other leg)
Use:
\(LS^2 + YS^2 = YL^2\)
Let LS = x:
\(x^2 + 6.3^2 = 15.4^2\)
Calculate:
\(x^2 + 39.69 = 237.16\)
\(x^2 = 237.16 - 39.69\)
\(x^2 = 197.47\)
\(x ≈ \sqrt{197.47} ≈ 14.0\)
**LS ≈ 14.0 km**
---
### Question 5
#### Find the length of JW:
Using the Pythagorean theorem:
- JE = 4.8 (one leg)
- EW = 28.6 (the other leg)
Use:
\(JW^2 + JE^2 = EW^2\)
Let JW = x:
\(x^2 + 4.8^2 = 28.6^2\)
Calculate:
\(x^2 + 23.04 = 817.96\)
\(x^2 = 817.96 - 23.04\)
\(x^2 = 794.92\)
\(x ≈ \sqrt{794.92} ≈ 28.2\)
**JW ≈ 28.2**
---
### Question 6
#### Find the length of the other leg:
Using the Pythagorean theorem:
- One leg = 10 cm
- Hypotenuse = 50.5 cm
Let the unknown leg = x:
\(x^2 + 10^2 = 50.5^2\)
Calculate:
\(x^2 + 100 = 2550.25\)
\(x^2 = 2550.25 - 100\)
\(x^2 = 2450.25\)
\(x ≈ \sqrt{2450.25} ≈ 49.5\)
**The other leg ≈ 49.5 cm**
---
### Question 7
For any video-related question, ensure to check the provided materials or links elsewhere, as I can’t provide or display video content.
Feel free to ask if you need further assistance on specific parts!