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Original Question
In birds, sex is determined by ZW chromosome inheritance. Males are ZZ and females are ZW. Within pigeon populations there is a...Question
In birds, sex is determined by ZW chromosome inheritance. Males are ZZ and females are ZW. Within pigeon populations there is a recessive, Z-linked allele that is lethal in embryos. What is the expected sex ratio in the offspring of a cross between a male that is heterozygous for the lethal allele and a wildtype female?
1:2 male to female
3:1 male to female
2:1 male to female
1:2 male to female
3:1 male to female
2:1 male to female
Answers
Answered by
GPT-4o mini
To determine the expected sex ratio of offspring in a cross between a male pigeon that is heterozygous for a lethal Z-linked allele and a wildtype female, we first need to understand the genetic setup:
- The male is heterozygous for the lethal allele on the Z chromosome, so his genotype is Z(A)Z, where Z(A) represents the Z chromosome carrying the lethal allele and Z represents the Z chromosome without the lethal allele.
- The female, being wildtype, has the ZW genotype (the W chromosome is not involved in sex-linked lethals).
Let's set up the possible gametes produced by each parent:
- The male (Z(A)Z) can produce two types of gametes: Z(A) and Z.
- The female (ZW) can produce two types of gametes: Z and W.
We can construct a Punnett square to visualize the possible combinations:
```
Z W
----------------
Z(A) | Z(A)Z | Z(A)W |
----------------
Z | ZZ | ZW |
```
Now let's analyze the offspring:
1. **Z(A)Z**: This genotype results in a male (ZZ) that carries the lethal allele, and since it is lethal, these embryos do not survive.
2. **Z(A)W**: This genotype results in a female (ZW) who carries the lethal allele but does survive.
3. **ZZ**: This genotype results in a male (ZZ) that is unaffected and does survive.
4. **ZW**: This genotype results in a female (ZW) that is unaffected.
From this, we can observe the following outcomes:
- Males that result from the cross:
- ZZ (survives)
- Z(A)Z (does not survive, lethal)
- Females that result from the cross:
- ZW (survives)
- Z(A)W (survives)
Therefore, out of the potential offspring:
- There are 2 male possibilities, but only one (ZZ) survives.
- There are 2 female possibilities, both of which (ZW and Z(A)W) survive.
As a result:
- The living males: 1 (ZZ)
- The living females: 2 (ZW and Z(A)W)
Thus, the expected sex ratio of surviving offspring is:
**1 male : 2 females**, which can also be expressed as a ratio of **2:1 male to female**.
So, the correct answer is:
**2:1 male to female**.
- The male is heterozygous for the lethal allele on the Z chromosome, so his genotype is Z(A)Z, where Z(A) represents the Z chromosome carrying the lethal allele and Z represents the Z chromosome without the lethal allele.
- The female, being wildtype, has the ZW genotype (the W chromosome is not involved in sex-linked lethals).
Let's set up the possible gametes produced by each parent:
- The male (Z(A)Z) can produce two types of gametes: Z(A) and Z.
- The female (ZW) can produce two types of gametes: Z and W.
We can construct a Punnett square to visualize the possible combinations:
```
Z W
----------------
Z(A) | Z(A)Z | Z(A)W |
----------------
Z | ZZ | ZW |
```
Now let's analyze the offspring:
1. **Z(A)Z**: This genotype results in a male (ZZ) that carries the lethal allele, and since it is lethal, these embryos do not survive.
2. **Z(A)W**: This genotype results in a female (ZW) who carries the lethal allele but does survive.
3. **ZZ**: This genotype results in a male (ZZ) that is unaffected and does survive.
4. **ZW**: This genotype results in a female (ZW) that is unaffected.
From this, we can observe the following outcomes:
- Males that result from the cross:
- ZZ (survives)
- Z(A)Z (does not survive, lethal)
- Females that result from the cross:
- ZW (survives)
- Z(A)W (survives)
Therefore, out of the potential offspring:
- There are 2 male possibilities, but only one (ZZ) survives.
- There are 2 female possibilities, both of which (ZW and Z(A)W) survive.
As a result:
- The living males: 1 (ZZ)
- The living females: 2 (ZW and Z(A)W)
Thus, the expected sex ratio of surviving offspring is:
**1 male : 2 females**, which can also be expressed as a ratio of **2:1 male to female**.
So, the correct answer is:
**2:1 male to female**.