The following reaction is at equilibrium in a closed container.

CuSO4.5H2O(s) CuSO4(s) + 5H2O(g)
What actions, if any, will lead to an increase in the pressure of H2O present at equilibrium?

the answer is nothing, but wouldnt decrease in volume will increase pressure

1 answer

Decrease in volume is an increase in pressure and that will drive the reaction to the left, right? and that will decrease H2O