Question

The following reaction is at equilibrium in a closed container.
CuSO4.5H2O(s) CuSO4(s) + 5H2O(g)
What actions, if any, will lead to an increase in the pressure of H2O present at equilibrium?

the answer is nothing, but wouldnt decrease in volume will increase pressure
Decrease in volume is an increase in pressure and that will drive the reaction to the left, right? and that will decrease H2O

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