Question
Solve the following quadratic equation using square roots: (x+12)2=9
.(1 point)
Responses
{−3,−21}
left brace negative 3 comma negative 21 right brace
{−9,−15}
left brace negative 9 comma negative 15 right brace
{15,9}
left brace 15 comma negative 9 right brace
{−7.5,−16.5}
.(1 point)
Responses
{−3,−21}
left brace negative 3 comma negative 21 right brace
{−9,−15}
left brace negative 9 comma negative 15 right brace
{15,9}
left brace 15 comma negative 9 right brace
{−7.5,−16.5}
Answers
Answered by
GPT-4o mini
To solve the quadratic equation \((x + 12)^2 = 9\) using square roots, follow these steps:
1. Take the square root of both sides:
\[
x + 12 = \pm 3
\]
2. This gives us two separate equations to solve:
\[
x + 12 = 3 \quad \text{and} \quad x + 12 = -3
\]
3. Solve each equation for \(x\):
- For \(x + 12 = 3\):
\[
x = 3 - 12
\]
\[
x = -9
\]
- For \(x + 12 = -3\):
\[
x = -3 - 12
\]
\[
x = -15
\]
Thus, the solutions to the equation \((x + 12)^2 = 9\) are:
\[
x = -9 \quad \text{and} \quad x = -15
\]
Therefore, the solution set is \(\{-9, -15\}\).
The correct response is:
\(\{-9, -15\}\)
1. Take the square root of both sides:
\[
x + 12 = \pm 3
\]
2. This gives us two separate equations to solve:
\[
x + 12 = 3 \quad \text{and} \quad x + 12 = -3
\]
3. Solve each equation for \(x\):
- For \(x + 12 = 3\):
\[
x = 3 - 12
\]
\[
x = -9
\]
- For \(x + 12 = -3\):
\[
x = -3 - 12
\]
\[
x = -15
\]
Thus, the solutions to the equation \((x + 12)^2 = 9\) are:
\[
x = -9 \quad \text{and} \quad x = -15
\]
Therefore, the solution set is \(\{-9, -15\}\).
The correct response is:
\(\{-9, -15\}\)
There are no human answers yet. A form for humans to post answers is coming very soon!