To solve the quadratic equation \( x^2 - 22x + 1 = 15 \) by completing the square, we first rearrange the equation:
\[ x^2 - 22x + 1 - 15 = 0 \]
This simplifies to:
\[ x^2 - 22x - 14 = 0 \]
Now, we'll complete the square for the expression \( x^2 - 22x \).
- Take half of the coefficient of \( x \) (which is -22), square it, and add it to both sides:
Half of -22 is -11, and squaring -11 gives \( 121 \).
- Rewrite the equation by adding \( 121 \) to both sides:
\[ x^2 - 22x + 121 = 14 + 121 \]
This simplifies to:
\[ (x - 11)^2 = 135 \]
- Now take the square root of both sides:
\[ x - 11 = \pm \sqrt{135} \]
- Finally, solve for \( x \):
\[ x = 11 \pm \sqrt{135} \]
Now let's simplify \( \sqrt{135} \):
\[ \sqrt{135} = \sqrt{9 \times 15} = 3\sqrt{15} \]
So, we have:
\[ x = 11 \pm 3\sqrt{15} \]
Thus, the solutions are:
\[ x = 11 + 3\sqrt{15}, \quad 11 - 3\sqrt{15} \]
The correct response from the options provided is:
x = 11 + 3√15, 11 - 3√15.