To solve the equation \( t^2 - 29 = 7 \), we can start by isolating \( t^2 \).
- First, add 29 to both sides of the equation:
\[ t^2 - 29 + 29 = 7 + 29 \] \[ t^2 = 36 \]
- Next, take the square root of both sides. Remember that taking the square root gives us both a positive and a negative solution:
\[ t = \pm \sqrt{36} \] \[ t = \pm 6 \]
Thus, the solutions for \( t \) are:
\[ t = 6 \quad \text{or} \quad t = -6 \]
So, the final answers are:
\[ t = 6 \quad \text{or} \quad t = -6 \]