To analyze the function \( A(w) = w^2 + 5w \), we can rewrite it in a standard quadratic form:
\[ A(w) = w^2 + 5w \]
This is a quadratic function that opens upwards (since the coefficient of \( w^2 \) is positive). The vertex of a quadratic function in the form \( f(w) = aw^2 + bw + c \) occurs at \( w = -\frac{b}{2a} \).
For our function:
- \( a = 1 \)
- \( b = 5 \)
Thus, the vertex \( w \) is computed as:
\[ w = -\frac{5}{2(1)} = -\frac{5}{2} \]
Since the function opens upwards, this means the minimum value occurs at \( w = -\frac{5}{2} \) and the function has no maximum value. Therefore, the correct relationship that describes \( A(w) \) is:
A(w) increases as w increases for all w > -2.5.
Now, looking at the original options presented:
- A(w) has a minimum value at w=5.
- A(w) increases as w increases when w > 0.
- A(w) increases as w increases for 0 < w < 5.
- A(w) has a maximum value at w=5.
The most accurate response based on the characteristics of the quadratic function is:
A(w) increases as w increases when w > 0.
This is because while \( A(w) \) is a quadratic function with minimum value at \( w = -2.5 \), we can say \( A(w) \) does indeed increase for \( w > 0 \). Hence, this is the best option among the responses provided.