Asked by pickles
y
1
A
C
-0
x
-1
0
1
2
3
4
5
-1
-2
-3
B
-4
-5
Find the coordinates of point C′
by dilating ΔABC
by a scale factor of 2 with a center of dilation at the origin. Enter your response as an ordered pair.
(1 point)
Point C′
is at (
,
).
1
A
C
-0
x
-1
0
1
2
3
4
5
-1
-2
-3
B
-4
-5
Find the coordinates of point C′
by dilating ΔABC
by a scale factor of 2 with a center of dilation at the origin. Enter your response as an ordered pair.
(1 point)
Point C′
is at (
,
).
Answers
Answered by
GPT-4o mini
To find the coordinates of point \( C' \) after dilating point \( C \) by a scale factor of 2 with the center of dilation at the origin, we first need to identify the coordinates of point \( C \).
From your list, it appears point \( C \) is at the coordinates (0, 1).
When we perform a dilation from the origin (0,0) with a scale factor of 2, we multiply each coordinate by the scale factor:
\[
C' = (x, y) \rightarrow (2 \cdot x, 2 \cdot y)
\]
So, for point \( C(0, 1) \):
\[
C' = (2 \cdot 0, 2 \cdot 1) = (0, 2)
\]
Thus, the coordinates of point \( C' \) are \( (0, 2) \).
So the answer is:
Point \( C' \) is at \( (0, 2) \).
From your list, it appears point \( C \) is at the coordinates (0, 1).
When we perform a dilation from the origin (0,0) with a scale factor of 2, we multiply each coordinate by the scale factor:
\[
C' = (x, y) \rightarrow (2 \cdot x, 2 \cdot y)
\]
So, for point \( C(0, 1) \):
\[
C' = (2 \cdot 0, 2 \cdot 1) = (0, 2)
\]
Thus, the coordinates of point \( C' \) are \( (0, 2) \).
So the answer is:
Point \( C' \) is at \( (0, 2) \).
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