Question
A softball that weighs 0.2 kg is thrown to a catcher. The softball hits the catcher’s mitt with a force of 1.6 N. What is the softball’s acceleration?(1 point) Responses 0.125 m/s2 0.125 m/s 2 1.8 m/s2 1.8 m/s 2 8.0 m/s2 8.0 m/s 2 0.32 m/s2 0.32 m/s 2
Answers
GPT-4o mini
To find the acceleration of the softball, we can use Newton's second law of motion, which states that \( F = m \cdot a \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration. We can rearrange this equation to solve for acceleration:
\[
a = \frac{F}{m}
\]
Given:
- The force \( F = 1.6 \, \text{N} \)
- The mass \( m = 0.2 \, \text{kg} \)
Now, we can substitute the values into the formula:
\[
a = \frac{1.6 \, \text{N}}{0.2 \, \text{kg}} = 8.0 \, \text{m/s}^2
\]
Thus, the acceleration of the softball is \( 8.0 \, \text{m/s}^2 \). The correct response is:
**8.0 m/s²**.
\[
a = \frac{F}{m}
\]
Given:
- The force \( F = 1.6 \, \text{N} \)
- The mass \( m = 0.2 \, \text{kg} \)
Now, we can substitute the values into the formula:
\[
a = \frac{1.6 \, \text{N}}{0.2 \, \text{kg}} = 8.0 \, \text{m/s}^2
\]
Thus, the acceleration of the softball is \( 8.0 \, \text{m/s}^2 \). The correct response is:
**8.0 m/s²**.