Question

Use the properties of operations to add 9(k+13)+10(12k−1)
.

Answer 1

To simplify the expression \( 9(k+13) + 10(12k-1) \), we will use the distributive property of operations.

1. **Distribute the 9 into the first term**:
\[
9(k + 13) = 9k + 9 \cdot 13 = 9k + 117
\]

2. **Distribute the 10 into the second term**:
\[
10(12k - 1) = 10 \cdot 12k + 10 \cdot (-1) = 120k - 10
\]

3. **Combine both results**:
\[
9(k+13) + 10(12k-1) = (9k + 117) + (120k - 10)
\]

4. **Combine like terms**:
- Combine the \( k \) terms: \( 9k + 120k = 129k \)
- Combine the constants: \( 117 - 10 = 107 \)

Putting it all together, we have:
\[
9(k+13) + 10(12k-1) = 129k + 107
\]

Thus, the simplified expression is:
\[
\boxed{129k + 107}
\]