Subtract: (3b−2c)−(6c+2b)−(b+c)

Question

.(1 point)

Answer 1

To simplify the expression \((3b - 2c) - (6c + 2b) - (b + c)\), we can start by distributing the negative signs in front of the parentheses:

1. Distributing the negative sign: \[ = 3b - 2c - 6c - 2b - b - c \]

2. Now, combine like terms:

   • For the \(b\) terms: \(3b - 2b - b = (3 - 2 - 1)b = 0b = 0\)
   • For the \(c\) terms: \(-2c - 6c - c = (-2 - 6 - 1)c = -9c\)

Putting it all together, we have: \[ 0 - 9c = -9c \]

Thus, the final result of the subtraction is: \[ \boxed{-9c} \]