Question
A cone has a radius of 5cm and a side of 9cm
What is the volume of the cone in cubic centimeters? Use 3.14 for pi. Round your answer to the nearest tenth.
What is the volume of the cone in cubic centimeters? Use 3.14 for pi. Round your answer to the nearest tenth.
Answers
GPT-4o mini
To calculate the volume of a cone, we can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the cone's base,
- \( h \) is the height of the cone, and
- \( \pi \) is approximately 3.14.
We are given:
- Radius \( r = 5 \) cm
- Slant height (side) = 9 cm.
To find the height \( h \) of the cone, we can use the Pythagorean theorem. The relationship involves the radius, height, and slant height as follows:
\[
s^2 = r^2 + h^2
\]
Where \( s \) is the slant height. Rearranging the equation for height \( h \) gives us:
\[
h^2 = s^2 - r^2
\]
Substituting the known values:
\[
s = 9 \, \text{cm}, \quad r = 5 \, \text{cm}
\]
Calculating \( h^2 \):
\[
h^2 = 9^2 - 5^2 = 81 - 25 = 56
\]
Now taking the square root to find \( h \):
\[
h = \sqrt{56} \approx 7.48 \, \text{cm}
\]
Now we can plug the values of \( r \) and \( h \) back into the volume formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
Calculating \( r^2 \):
\[
r^2 = 5^2 = 25
\]
Now substituting the known values into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times 25 \times 7.48
\]
Calculating the product:
1. Multiply \( 25 \times 7.48 = 186.96 \)
2. Then multiply by \( 3.14 \):
\[
3.14 \times 186.96 \approx 588.0144
\]
3. Finally, take one third of that:
\[
V \approx \frac{588.0144}{3} \approx 196.0048
\]
Rounding to the nearest tenth, we have:
\[
\boxed{196.0} \, \text{cubic centimeters}
\]
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius of the cone's base,
- \( h \) is the height of the cone, and
- \( \pi \) is approximately 3.14.
We are given:
- Radius \( r = 5 \) cm
- Slant height (side) = 9 cm.
To find the height \( h \) of the cone, we can use the Pythagorean theorem. The relationship involves the radius, height, and slant height as follows:
\[
s^2 = r^2 + h^2
\]
Where \( s \) is the slant height. Rearranging the equation for height \( h \) gives us:
\[
h^2 = s^2 - r^2
\]
Substituting the known values:
\[
s = 9 \, \text{cm}, \quad r = 5 \, \text{cm}
\]
Calculating \( h^2 \):
\[
h^2 = 9^2 - 5^2 = 81 - 25 = 56
\]
Now taking the square root to find \( h \):
\[
h = \sqrt{56} \approx 7.48 \, \text{cm}
\]
Now we can plug the values of \( r \) and \( h \) back into the volume formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
Calculating \( r^2 \):
\[
r^2 = 5^2 = 25
\]
Now substituting the known values into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times 25 \times 7.48
\]
Calculating the product:
1. Multiply \( 25 \times 7.48 = 186.96 \)
2. Then multiply by \( 3.14 \):
\[
3.14 \times 186.96 \approx 588.0144
\]
3. Finally, take one third of that:
\[
V \approx \frac{588.0144}{3} \approx 196.0048
\]
Rounding to the nearest tenth, we have:
\[
\boxed{196.0} \, \text{cubic centimeters}
\]