Asked by star
Which of the following equations has a solution different from the rest? (1 point) Responses 3/4x+5=−1/4 Start Fraction 3 over 4 End Fraction x plus 5 equals negative Start Fraction 1 over 4 End Fraction −0.35x−0.52=1.93 negative 0.35 x minus 0.52 equals 1.93 1/2x−3=1/2 Start Fraction 1 over 2 End Fraction x minus 3 equals Start Fraction 1 over 2 End Fraction −1/7x−3/4=1/4
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Answered by
GPT-4o mini
To determine which equation has a different solution from the rest, we can solve each equation one by one.
1. **Equation 1: \( \frac{3}{4}x + 5 = -\frac{1}{4} \)**
\(\frac{3}{4}x = -\frac{1}{4} - 5\)
\(\frac{3}{4}x = -\frac{1}{4} - \frac{20}{4} = -\frac{21}{4}\)
\(x = -\frac{21}{4} \cdot \frac{4}{3} = -\frac{21}{3} = -7\)
2. **Equation 2: \(-0.35x - 0.52 = 1.93\)**
\(-0.35x = 1.93 + 0.52\)
\(-0.35x = 2.45\)
\(x = \frac{2.45}{-0.35} \approx -7\)
3. **Equation 3: \(\frac{1}{2}x - 3 = \frac{1}{2}\)**
\(\frac{1}{2}x = \frac{1}{2} + 3\)
\(\frac{1}{2}x = \frac{1}{2} + \frac{6}{2} = \frac{7}{2}\)
\(x = 7\)
4. **Equation 4: \(-\frac{1}{7}x - \frac{3}{4} = \frac{1}{4}\)**
\(-\frac{1}{7}x = \frac{1}{4} + \frac{3}{4}\)
\(-\frac{1}{7}x = 1\)
\(x = -7\)
Now we have the solutions for each equation:
- **Equation 1:** \(x = -7\)
- **Equation 2:** \(x \approx -7\)
- **Equation 3:** \(x = 7\)
- **Equation 4:** \(x = -7\)
The equation that has a solution different from the rest is **Equation 3**, which has the solution \(x = 7\). The others yield \(x \approx -7\).
1. **Equation 1: \( \frac{3}{4}x + 5 = -\frac{1}{4} \)**
\(\frac{3}{4}x = -\frac{1}{4} - 5\)
\(\frac{3}{4}x = -\frac{1}{4} - \frac{20}{4} = -\frac{21}{4}\)
\(x = -\frac{21}{4} \cdot \frac{4}{3} = -\frac{21}{3} = -7\)
2. **Equation 2: \(-0.35x - 0.52 = 1.93\)**
\(-0.35x = 1.93 + 0.52\)
\(-0.35x = 2.45\)
\(x = \frac{2.45}{-0.35} \approx -7\)
3. **Equation 3: \(\frac{1}{2}x - 3 = \frac{1}{2}\)**
\(\frac{1}{2}x = \frac{1}{2} + 3\)
\(\frac{1}{2}x = \frac{1}{2} + \frac{6}{2} = \frac{7}{2}\)
\(x = 7\)
4. **Equation 4: \(-\frac{1}{7}x - \frac{3}{4} = \frac{1}{4}\)**
\(-\frac{1}{7}x = \frac{1}{4} + \frac{3}{4}\)
\(-\frac{1}{7}x = 1\)
\(x = -7\)
Now we have the solutions for each equation:
- **Equation 1:** \(x = -7\)
- **Equation 2:** \(x \approx -7\)
- **Equation 3:** \(x = 7\)
- **Equation 4:** \(x = -7\)
The equation that has a solution different from the rest is **Equation 3**, which has the solution \(x = 7\). The others yield \(x \approx -7\).
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