Asked by star
does x/-3.2x=1.8 have the same answer as 1.8x=3.2?
Answers
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Answered by
GPT-4o mini
To determine whether the equations \( \frac{x}{-3.2x} = 1.8 \) and \( 1.8x = 3.2 \) have the same solution, we can solve each equation separately.
### Solving the first equation:
Starting with the equation:
\[
\frac{x}{-3.2x} = 1.8
\]
Assuming \( x \neq 0 \), we can simplify \( \frac{x}{-3.2x} \):
\[
\frac{1}{-3.2} = 1.8
\]
Now, we can multiply both sides by \(-3.2\):
\[
1 = 1.8 \times (-3.2)
\]
Calculating \( 1.8 \times (-3.2) \):
\[
1.8 \times -3.2 = -5.76
\]
Thus:
\[
1 = -5.76
\]
This statement is incorrect, indicating that there are no solutions to the first equation.
### Solving the second equation:
Now let’s solve the second equation:
\[
1.8x = 3.2
\]
To solve for \( x \), divide both sides by \( 1.8 \):
\[
x = \frac{3.2}{1.8}
\]
Calculating \( \frac{3.2}{1.8} \):
\[
x \approx 1.7778 \quad (\text{or } \frac{16}{9})
\]
### Conclusion:
- The first equation \( \frac{x}{-3.2x} = 1.8 \) has no solutions.
- The second equation \( 1.8x = 3.2 \) has a solution \( x \approx 1.7778 \).
Therefore, the two equations do **not** have the same answer.
### Solving the first equation:
Starting with the equation:
\[
\frac{x}{-3.2x} = 1.8
\]
Assuming \( x \neq 0 \), we can simplify \( \frac{x}{-3.2x} \):
\[
\frac{1}{-3.2} = 1.8
\]
Now, we can multiply both sides by \(-3.2\):
\[
1 = 1.8 \times (-3.2)
\]
Calculating \( 1.8 \times (-3.2) \):
\[
1.8 \times -3.2 = -5.76
\]
Thus:
\[
1 = -5.76
\]
This statement is incorrect, indicating that there are no solutions to the first equation.
### Solving the second equation:
Now let’s solve the second equation:
\[
1.8x = 3.2
\]
To solve for \( x \), divide both sides by \( 1.8 \):
\[
x = \frac{3.2}{1.8}
\]
Calculating \( \frac{3.2}{1.8} \):
\[
x \approx 1.7778 \quad (\text{or } \frac{16}{9})
\]
### Conclusion:
- The first equation \( \frac{x}{-3.2x} = 1.8 \) has no solutions.
- The second equation \( 1.8x = 3.2 \) has a solution \( x \approx 1.7778 \).
Therefore, the two equations do **not** have the same answer.
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