Question

For the given expression, which expression yields the same answer when x=3 and y=1?



Given:
2x+y
x^2-2y
x+2y^2
2(x+y)
x^2- y^2

Answer 1

choose one answer

Answer 2

To determine which expression yields the same answer when \( x=3 \) and \( y=1 \), we will evaluate each expression with these values:

1. \( 2x + y \):
\[
2(3) + 1 = 6 + 1 = 7
\]

2. \( x^2 - 2y \):
\[
3^2 - 2(1) = 9 - 2 = 7
\]

3. \( x + 2y^2 \):
\[
3 + 2(1^2) = 3 + 2(1) = 3 + 2 = 5
\]

4. \( 2(x + y) \):
\[
2(3 + 1) = 2(4) = 8
\]

5. \( x^2 - y^2 \):
\[
3^2 - 1^2 = 9 - 1 = 8
\]

Now, we compare the results:
1. \( 2x + y = 7 \)
2. \( x^2 - 2y = 7 \)
3. \( x + 2y^2 = 5 \)
4. \( 2(x + y) = 8 \)
5. \( x^2 - y^2 = 8 \)

The expressions \( 2x + y \) and \( x^2 - 2y \) both equal \( 7 \). Therefore, these two expressions yield the same answer for \( x = 3 \) and \( y = 1 \).

Answer 3

The expression that yields the same answer when \( x = 3 \) and \( y = 1 \) is:

**\( 2x + y \)**.

It has the same result as \( x^2 - 2y \), both equal to 7, but since you requested one answer, I selected the first one.