Asked by Jayla
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An illustration shows a coordinate plane with four quadrants. The x-axis and y-axis both range from negative 7 to 7 in one unit increments. An upward slanting line is graphed on the coordinate plane. The line passes through points plotted at left parenthesis negative 6 comma negative 1 right parenthesis, left parenthesis 0 comma 0 right parenthesis, and left parenthesis 6 comma 1 right parenthesis.
Determine if the given graph is the graph of the function y=16x
. Enter 1 for yes. Enter 2 for no.
(1 point)
Remaining Attempts : 3
An illustration shows a coordinate plane with four quadrants. The x-axis and y-axis both range from negative 7 to 7 in one unit increments. An upward slanting line is graphed on the coordinate plane. The line passes through points plotted at left parenthesis negative 6 comma negative 1 right parenthesis, left parenthesis 0 comma 0 right parenthesis, and left parenthesis 6 comma 1 right parenthesis.
Determine if the given graph is the graph of the function y=16x
. Enter 1 for yes. Enter 2 for no.
(1 point)
Remaining Attempts : 3
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine if the line graphed on the coordinate plane is the graph of the function \( y = 16x \), we can analyze the points through which the line passes.
1. The function \( y = 16x \) means that for any value of \( x \), \( y \) is calculated as \( 16 \) times \( x \).
2. Let's check the points given:
- For the point \( (-6, -1) \):
\[
y = 16 \times (-6) = -96 \quad (\text{not } -1)
\]
- For the point \( (0, 0) \):
\[
y = 16 \times 0 = 0 \quad (\text{correct})
\]
- For the point \( (6, 1) \):
\[
y = 16 \times 6 = 96 \quad (\text{not } 1)
\]
Since the point \( (-6, -1) \) does not satisfy the equation, the point \( (6, 1) \) also does not satisfy \( y = 16x \), while the point \( (0, 0) \) does.
Thus, not all points on the line agree with the function \( y = 16x \).
The answer is 2 for no.
1. The function \( y = 16x \) means that for any value of \( x \), \( y \) is calculated as \( 16 \) times \( x \).
2. Let's check the points given:
- For the point \( (-6, -1) \):
\[
y = 16 \times (-6) = -96 \quad (\text{not } -1)
\]
- For the point \( (0, 0) \):
\[
y = 16 \times 0 = 0 \quad (\text{correct})
\]
- For the point \( (6, 1) \):
\[
y = 16 \times 6 = 96 \quad (\text{not } 1)
\]
Since the point \( (-6, -1) \) does not satisfy the equation, the point \( (6, 1) \) also does not satisfy \( y = 16x \), while the point \( (0, 0) \) does.
Thus, not all points on the line agree with the function \( y = 16x \).
The answer is 2 for no.
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