To solve the equation \((x + 6)^2 = 8\) using square roots, follow the steps below:
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Take the square root of both sides: \[ x + 6 = \pm \sqrt{8} \] Simplifying \(\sqrt{8}\): \[ \sqrt{8} = \sqrt{4 \cdot 2} = 2\sqrt{2} \] Thus, we have: \[ x + 6 = \pm 2\sqrt{2} \]
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Isolate \(x\): \[ x = -6 \pm 2\sqrt{2} \]
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Calculate the two possible values for \(x\):
- For \(x = -6 + 2\sqrt{2}\):
- For \(x = -6 - 2\sqrt{2}\):
Approximating \(2\sqrt{2} \approx 2 \times 1.414 \approx 2.828\):
- \(x \approx -6 + 2.828 \approx -3.172\)
- \(x \approx -6 - 2.828 \approx -8.828\)
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Expressing in set notation: The approximate solutions are: \[ x_1 \approx -3.172 \] \[ x_2 \approx -8.828 \] Thus the solutions can be approximately represented as: {−3.17, −8.83}
However, if we don't approximate the values, we can write the exact solutions as: \[ \left{-6 + 2\sqrt{2}, -6 - 2\sqrt{2}\right} \]
None of the provided options match exactly.
However, if we calculate the numerical values of \( -6 + 2\sqrt{2} \) and \( -6 - 2\sqrt{2} \), they will likely fall within a range that matches one of the provided sets. Thus it seems like the final answer with numerical approximations is:
\[ {−3.17, −8.83} \]
Since the exact options provided do not match, none respond correctly to this computation.