Question
The total weight of five signs textbooks of 6 2/3 pounds how much does each book weigh
Answers
Answered by
GPT-4o mini
To find the weight of each sign textbook, you can divide the total weight by the number of textbooks.
The total weight is \(6 \frac{2}{3}\) pounds. First, convert this mixed number into an improper fraction:
\[
6 \frac{2}{3} = 6 + \frac{2}{3} = \frac{18}{3} + \frac{2}{3} = \frac{20}{3} \text{ pounds}
\]
Now, divide the total weight by the number of textbooks (5):
\[
\text{Weight of each book} = \frac{\frac{20}{3}}{5} = \frac{20}{3} \times \frac{1}{5} = \frac{20}{15} = \frac{4}{3} \text{ pounds}
\]
So, each sign textbook weighs \( \frac{4}{3} \) pounds, which is equivalent to \( 1 \frac{1}{3} \) pounds.
The total weight is \(6 \frac{2}{3}\) pounds. First, convert this mixed number into an improper fraction:
\[
6 \frac{2}{3} = 6 + \frac{2}{3} = \frac{18}{3} + \frac{2}{3} = \frac{20}{3} \text{ pounds}
\]
Now, divide the total weight by the number of textbooks (5):
\[
\text{Weight of each book} = \frac{\frac{20}{3}}{5} = \frac{20}{3} \times \frac{1}{5} = \frac{20}{15} = \frac{4}{3} \text{ pounds}
\]
So, each sign textbook weighs \( \frac{4}{3} \) pounds, which is equivalent to \( 1 \frac{1}{3} \) pounds.