To graph the equation \(y = 23x - 1\), we can start by finding some key points by substituting values for \(x\).
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Finding Points:
- When \(x = 0\): \[ y = 23(0) - 1 = -1 \quad \text{(Point: (0, -1))} \]
- When \(x = 1\): \[ y = 23(1) - 1 = 22 \quad \text{(Point: (1, 22))} \]
- When \(x = -1\): \[ y = 23(-1) - 1 = -24 \quad \text{(Point: (-1, -24))} \]
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Plotting Points: You can plot the points you've calculated: (0, -1), (1, 22), and (-1, -24) on the coordinate plane.
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Graphing the Line: After plotting these points, draw a straight line through them and extend the line with arrows at both ends.
From the options provided in the question, the plotted points and line need to represent the equation \(y = 23x - 1\) accurately. The correct graph will have a very steep slope since the coefficient of \(x\) is 23, meaning that as \(x\) increases, \(y\) will increase significantly.
Given the options, the correct graph should reflect these calculations and match the resulting points you find from \(y = 23x - 1\). Based on the descriptions provided, you would need the graph that passes through (0, -1) and has a steep incline corresponding to the slope of 23.