To find the total mass of the reactants from the reaction \( \text{FeCl}_3 + 3\text{H}_2\text{O} \), we need to calculate the mass of each reactant based on their formula and the atomic masses provided.
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Calculate the mass of \(\text{FeCl}_3\):
- Iron (Fe): 1 atom × 56 amu = 56 amu
- Chlorine (Cl): 3 atoms × 35 amu = 105 amu
- Total mass of \(\text{FeCl}_3\) = 56 amu + 105 amu = 161 amu
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Calculate the mass of \(3\text{H}_2\text{O}\):
- Hydrogen (H): 2 atoms in \(H_2O\) × 1 amu = 2 amu
- Oxygen (O): 1 atom × 16 amu = 16 amu
- Total mass of \(H_2O\) = 2 amu + 16 amu = 18 amu
- For \(3\text{H}_2\text{O}\): 3 × 18 amu = 54 amu
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Total mass of reactants:
- Mass of \(\text{FeCl}_3\) + Mass of \(3\text{H}_2\text{O}\) = 161 amu + 54 amu = 215 amu
So, the total mass of the reactants is 215 amu.