To determine the total mass of the reactants in the reaction of iron chloride (FeCl3) and water (H2O), we first need to calculate the molar masses of these compounds.
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Molar mass of Iron(III) chloride (FeCl3):
- Iron (Fe): approximately 55.85 amu
- Chlorine (Cl): approximately 35.45 amu
- Molar mass of FeCl3 = 55.85 + (3 × 35.45) = 55.85 + 106.35 = 162.20 amu
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Molar mass of Water (H2O):
- Hydrogen (H): approximately 1.01 amu
- Oxygen (O): approximately 16.00 amu
- Molar mass of H2O = (2 × 1.01) + 16.00 = 2.02 + 16.00 = 18.02 amu
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Total mass of the reactants (FeCl3 + H2O):
- Total mass = Molar mass of FeCl3 + Molar mass of H2O = 162.20 amu + 18.02 amu = 180.22 amu
None of the provided responses (108 amu, 215 amu, 179 amu, 161 amu) correctly matches the calculated total mass of the reactants (180.22 amu). Please double-check the problem and the compounds involved to ensure accuracy.