To factor the quadratic equation \( x^2 + 14x + 24 = 0 \), we need to find two numbers that add up to 14 (the coefficient of \( x \)) and multiply to 24 (the constant term).
The numbers that satisfy these conditions are 12 and 2, since:
- \( 12 + 2 = 14 \)
- \( 12 \times 2 = 24 \)
Thus, we can write the factored form of the equation as:
\[ (x + 12)(x + 2) = 0 \]
So the filled blanks would be:
\[ (x + 12)(x + 2) = 0 \]