Question

please expand -5/6(9b-12)

Answer 1

To expand the expression \(-\frac{5}{6}(9b - 12)\), you will distribute \(-\frac{5}{6}\) to both terms inside the parentheses:

\[
-\frac{5}{6}(9b) + -\frac{5}{6}(-12)
\]

Now, calculate each term separately:

1. For the first term:
\[
-\frac{5}{6} \times 9b = -\frac{45}{6}b = -\frac{15}{2}b \quad \text{(simplifying by dividing numerator and denominator by 3)}
\]

2. For the second term:
\[
-\frac{5}{6} \times -12 = \frac{60}{6} = 10
\]

Now, combine the results from both terms:

\[
-\frac{15}{2}b + 10
\]

So, the expanded form of \(-\frac{5}{6}(9b - 12)\) is:

\[
-\frac{15}{2}b + 10
\]