please expand -5/6(9b-12)

Answer 1

To expand the expression \(-\frac{5}{6}(9b - 12)\), you will distribute \(-\frac{5}{6}\) to both terms inside the parentheses:

\[ -\frac{5}{6}(9b) + -\frac{5}{6}(-12) \]

Now, calculate each term separately:

1. For the first term: \[ -\frac{5}{6} \times 9b = -\frac{45}{6}b = -\frac{15}{2}b \quad \text{(simplifying by dividing numerator and denominator by 3)} \]

2. For the second term: \[ -\frac{5}{6} \times -12 = \frac{60}{6} = 10 \]

Now, combine the results from both terms:

\[ -\frac{15}{2}b + 10 \]

So, the expanded form of \(-\frac{5}{6}(9b - 12)\) is:

\[ -\frac{15}{2}b + 10 \]