Question

Use the following function rule to find f(0).

f(x)=6(12)^x+11
f(1)=___

Answer 1

To find \( f(0) \) using the function rule \( f(x) = 6(12)^x + 11 \), we substitute \( x = 0 \) into the function:

\[
f(0) = 6(12)^0 + 11
\]

Since \( (12)^0 = 1 \):

\[
f(0) = 6(1) + 11 = 6 + 11 = 17
\]

Now, to find \( f(1) \):

\[
f(1) = 6(12)^1 + 11
\]

Substituting \( 12^1 = 12 \):

\[
f(1) = 6(12) + 11 = 72 + 11 = 83
\]

So, \( f(1) = 83 \).

In summary,
\[
f(0) = 17 \quad \text{and} \quad f(1) = 83
\]