Question
Mike draws a triangle and dilates it by a scale factor of 2.5. If the triangle’s original dimensions are 4 inches high and 6 inches along its base, what is the area in square inches of Mike’s dilated triangle?M
(1 point)
Responses
150
150
60
60
75
75
24
(1 point)
Responses
150
150
60
60
75
75
24
Answers
GPT-4o mini
To find the area of Mike's dilated triangle, we can follow these steps:
1. **Calculate the area of the original triangle:**
The area \( A \) of a triangle is given by the formula:
\[
A = \frac{1}{2} \times \text{base} \times \text{height}
\]
For the original triangle:
- Base = 6 inches
- Height = 4 inches
So the area of the original triangle is:
\[
A = \frac{1}{2} \times 6 \times 4 = \frac{1}{2} \times 24 = 12 \text{ square inches}
\]
2. **Use the scale factor to find the area of the dilated triangle:**
The area of a shape scales by the square of the scale factor when dilated. In this case, the scale factor is 2.5. Therefore, the area of the dilated triangle can be calculated as:
\[
\text{Area of dilated triangle} = \text{Area of original triangle} \times \text{(scale factor)}^2
\]
\[
= 12 \times (2.5)^2
\]
\[
= 12 \times 6.25 = 75 \text{ square inches}
\]
Therefore, the area of Mike's dilated triangle is **75 square inches**.
1. **Calculate the area of the original triangle:**
The area \( A \) of a triangle is given by the formula:
\[
A = \frac{1}{2} \times \text{base} \times \text{height}
\]
For the original triangle:
- Base = 6 inches
- Height = 4 inches
So the area of the original triangle is:
\[
A = \frac{1}{2} \times 6 \times 4 = \frac{1}{2} \times 24 = 12 \text{ square inches}
\]
2. **Use the scale factor to find the area of the dilated triangle:**
The area of a shape scales by the square of the scale factor when dilated. In this case, the scale factor is 2.5. Therefore, the area of the dilated triangle can be calculated as:
\[
\text{Area of dilated triangle} = \text{Area of original triangle} \times \text{(scale factor)}^2
\]
\[
= 12 \times (2.5)^2
\]
\[
= 12 \times 6.25 = 75 \text{ square inches}
\]
Therefore, the area of Mike's dilated triangle is **75 square inches**.