Choose the inequality that matches this situation.

Question

Company A charges a fee of $25 plus $0.20 per brouchure to print and deliver them. Company B charges $0.30 per brochure. How many would need to be ordered for Company A to cost more than Company B?

$0.20b+$ 0.3b > 25b

$0.20b+$ 0.3b < 25b

$25+$ 0.2b >$0.30b

$25+$ 0.2b <$0.30b

Answer 1

To determine when Company A charges more than Company B, we need to set up the cost equations for both companies.

• The cost for Company A is $C_A=25+0.20b$ where $b$ is the number of brochures.
• The cost for Company B is $C_B=0.30b$.

We want to find the inequality for when Company A's cost exceeds Company B's cost:

$$25+0.20b>0.30b$$

This means the correct inequality that matches the situation is:

$$\$25+\$0.20b>\$0.30b$$