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Select two values for x that would make 8 + 2x ≤ 20 true.

10

8

6

4

1 answer

To solve the inequality \( 8 + 2x \leq 20 \), we first isolate \( x \):

  1. Subtract 8 from both sides: \[ 2x \leq 20 - 8 \] \[ 2x \leq 12 \]

  2. Divide both sides by 2: \[ x \leq 6 \]

Now we need to select values for \( x \) that are less than or equal to 6.

From the provided options:

  • 10 \( \rightarrow \) Not valid (10 > 6)
  • 8 \( \rightarrow \) Not valid (8 > 6)
  • 6 \( \rightarrow \) Valid (6 = 6)
  • 4 \( \rightarrow \) Valid (4 < 6)

Thus, the two values for \( x \) that would make \( 8 + 2x \leq 20 \) true are 6 and 4.