Write the linear equation in point-slope form given a line that passes through the point (-14,8) and has a slope of -3

Answer 1

The point-slope form of a linear equation is given by the formula:

\[ y - y_1 = m(x - x_1) \]

where \((x_1, y_1)\) is a point on the line, and \(m\) is the slope. Given the point (-14, 8) and the slope of -3, we can substitute these values into the formula.

Here, \((x_1, y_1) = (-14, 8)\) and \(m = -3\). Plugging in these values, we get:

\[ y - 8 = -3(x - (-14)) \]

This simplifies to:

\[ y - 8 = -3(x + 14) \]

So, the equation of the line in point-slope form is:

\[ y - 8 = -3(x + 14) \]