Evaluate

Question

\[6+\dfrac{4}a+\dfrac b3\] when
\[a=4\] and
\[b=3\]

Answer 1

To evaluate the expression

\[ 6+\dfrac{4}a+\dfrac b3 \]

when \(a=4\) and \(b=3\), we start by substituting these values into the expression.

Substituting \(a=4\) into \(\dfrac{4}{a}\):

\[ \dfrac{4}{4} = 1 \]

Next, substituting \(b=3\) into \(\dfrac{b}{3}\):

\[ \dfrac{3}{3} = 1 \]

Now, we can substitute these results back into the original expression:

\[ 6 + 1 + 1 \]

Now we can perform the addition:

\[ 6 + 1 = 7 \]

\[ 7 + 1 = 8 \]

Thus, the evaluated result of the expression is

\[ \boxed{8} \]