Asked by swiss
Complete the square to solve the following quadratic equation: x2−22x+1=15
.(1 point)
Responses
x=11+14−−√, 11−14−−√
x equals 11 plus Start Root 14 End Root comma 11 minus Start Root 14 End Root
x=−11+14−−√, −11−14−−√
x equals negative 11 plus Start Root 14 End Root comma negative 11 minus Start Root 14 End Root
x=11+315−−√, 11−315−−√
x equals 11 plus 3 Start Root 15 End Root comma 11 minus 3 Start Root 15 End Root
x=−11+315−−√, −11−315−−√
.(1 point)
Responses
x=11+14−−√, 11−14−−√
x equals 11 plus Start Root 14 End Root comma 11 minus Start Root 14 End Root
x=−11+14−−√, −11−14−−√
x equals negative 11 plus Start Root 14 End Root comma negative 11 minus Start Root 14 End Root
x=11+315−−√, 11−315−−√
x equals 11 plus 3 Start Root 15 End Root comma 11 minus 3 Start Root 15 End Root
x=−11+315−−√, −11−315−−√
Answers
Answered by
GPT-4o mini
To solve the quadratic equation \( x^2 - 22x + 1 = 15 \) by completing the square, we follow these steps:
1. First, rearrange the equation:
\[
x^2 - 22x + 1 - 15 = 0
\]
which simplifies to:
\[
x^2 - 22x - 14 = 0
\]
2. Move the constant term to the other side:
\[
x^2 - 22x = 14
\]
3. To complete the square, take half of the coefficient of \( x \) (which is -22), square it, and add it to both sides. Half of -22 is -11, and squaring -11 gives 121:
\[
x^2 - 22x + 121 = 14 + 121
\]
So, we have:
\[
(x - 11)^2 = 135
\]
4. Next, take the square root of both sides:
\[
x - 11 = \pm \sqrt{135}
\]
5. Solve for \( x \):
\[
x = 11 \pm \sqrt{135}
\]
Thus, the solutions are:
\[
x = 11 + \sqrt{135}, \quad x = 11 - \sqrt{135}
\]
The final answer, matching the options provided, would be:
\[
x = 11 + 3\sqrt{15}, \quad 11 - 3\sqrt{15}
\]
Therefore, the correct response is:
**x=11+3√15, 11−3√15**
1. First, rearrange the equation:
\[
x^2 - 22x + 1 - 15 = 0
\]
which simplifies to:
\[
x^2 - 22x - 14 = 0
\]
2. Move the constant term to the other side:
\[
x^2 - 22x = 14
\]
3. To complete the square, take half of the coefficient of \( x \) (which is -22), square it, and add it to both sides. Half of -22 is -11, and squaring -11 gives 121:
\[
x^2 - 22x + 121 = 14 + 121
\]
So, we have:
\[
(x - 11)^2 = 135
\]
4. Next, take the square root of both sides:
\[
x - 11 = \pm \sqrt{135}
\]
5. Solve for \( x \):
\[
x = 11 \pm \sqrt{135}
\]
Thus, the solutions are:
\[
x = 11 + \sqrt{135}, \quad x = 11 - \sqrt{135}
\]
The final answer, matching the options provided, would be:
\[
x = 11 + 3\sqrt{15}, \quad 11 - 3\sqrt{15}
\]
Therefore, the correct response is:
**x=11+3√15, 11−3√15**
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