A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)

Question

Responses

8.2 N
8.2 N

7.8 N
7.8 N

1.6 N
1.6 N

40 N
40 N

Answer 1

To find the force with which the softball will hit the catcher’s mitt, we can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

where:

• \( F \) is the force,
• \( m \) is the mass, and
• \( a \) is the acceleration.

Given:

• \( m = 0.2 \) kg (mass of the softball)
• \( a = 8 \) m/s² (acceleration of the softball)

Now, substituting the values into the formula:

\[ F = 0.2 , \text{kg} \cdot 8 , \text{m/s}^2 \] \[ F = 1.6 , \text{N} \]

Therefore, the force with which the ball will hit the catcher’s mitt is 1.6 N.