To find which point is a distance of 3 from the point (-7, 4), we can use the distance formula:
\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
where \((x_1, y_1)\) is the point (-7, 4) and \((x_2, y_2)\) is the point we are checking.
We need to find the points that satisfy \(d = 3\).
Now, let's calculate the distance for each point:
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Point (4, 4): \[ d = \sqrt{(4 - (-7))^2 + (4 - 4)^2} = \sqrt{(4 + 7)^2 + (0)^2} = \sqrt{11^2} = 11 \quad (\text{Not 3}) \]
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Point (10, 4): \[ d = \sqrt{(10 - (-7))^2 + (4 - 4)^2} = \sqrt{(10 + 7)^2 + (0)^2} = \sqrt{17^2} = 17 \quad (\text{Not 3}) \]
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Point (−7, −1): \[ d = \sqrt{(-7 - (-7))^2 + (-1 - 4)^2} = \sqrt{(0)^2 + (-1 - 4)^2} = \sqrt{0 + (-5)^2} = \sqrt{25} = 5 \quad (\text{Not 3}) \]
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Point (−10, 4): \[ d = \sqrt{(-10 - (-7))^2 + (4 - 4)^2} = \sqrt{(-10 + 7)^2 + (0)^2} = \sqrt{(-3)^2 + (0)^2} = \sqrt{9} = 3 \quad (\text{Is 3}) \]
The point that has a distance of 3 from the point (-7, 4) is \(\boxed{(-10, 4)}\).