Asked by cynthia
(y^5)^3(y^3)^2/(y^4)^4
Answers
Answered by
DrBob222
I would do this if you mean this:
(y^5)^3*(y^3)^2/(y^4)^4 =
y^15*y^6/y^16 =
y^21/y^16 =
y^5
(y^5)^3*(y^3)^2/(y^4)^4 =
y^15*y^6/y^16 =
y^21/y^16 =
y^5
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