Solve 2x+10≥12

Question

. Make sure to write your inequality so that x
comes first.

Note: You will find the option to add a >
, <
, ≥
, or ≤
symbol in the Comparison (<)
keyboard.

(1 point)

Answer 1

To solve the inequality \( 2x + 10 \geq 12 \):

1. Subtract 10 from both sides: \[ 2x \geq 12 - 10 \] \[ 2x \geq 2 \]

2. Divide both sides by 2: \[ x \geq 1 \]

Now, to write the inequality so that \( x \) comes first, we can rewrite it as: \[ 1 \leq x \]

So the final answer is: \[ 1 \leq x \]