What rational number could be used as an exponent to rewrite 23−−√4
?(1 point)
?(1 point)
Answers
Answered by
GPT-4o mini
To rewrite \( \sqrt[4]{23} \) in exponential form, we can express it using rational exponents.
The fourth root of \( 23 \) can be expressed as:
\[
\sqrt[4]{23} = 23^{1/4}
\]
So the rational number that could be used as an exponent to rewrite \( \sqrt[4]{23} \) is \( \frac{1}{4} \).
The fourth root of \( 23 \) can be expressed as:
\[
\sqrt[4]{23} = 23^{1/4}
\]
So the rational number that could be used as an exponent to rewrite \( \sqrt[4]{23} \) is \( \frac{1}{4} \).
How can you rewrite 9^1/3
using a root?(1 point)
using a root?(1 point)
Answered by
GPT-4o mini
To rewrite \( 9^{1/3} \) using a root, we can express it as a cube root.
The expression \( 9^{1/3} \) can be rewritten as:
\[
\sqrt[3]{9}
\]
So, \( 9^{1/3} \) is equal to \( \sqrt[3]{9} \).
The expression \( 9^{1/3} \) can be rewritten as:
\[
\sqrt[3]{9}
\]
So, \( 9^{1/3} \) is equal to \( \sqrt[3]{9} \).
What is the simplified form of 27^1/3
?(1 point)
?(1 point)
Answered by
GPT-4o mini
To simplify \( 27^{1/3} \), we can find the cube root of \( 27 \).
Since \( 27 = 3^3 \), we have:
\[
27^{1/3} = (3^3)^{1/3}
\]
Using the property of exponents \((a^m)^n = a^{m \cdot n}\):
\[
(3^3)^{1/3} = 3^{3 \cdot \frac{1}{3}} = 3^1 = 3
\]
Therefore, the simplified form of \( 27^{1/3} \) is \( 3 \).
Since \( 27 = 3^3 \), we have:
\[
27^{1/3} = (3^3)^{1/3}
\]
Using the property of exponents \((a^m)^n = a^{m \cdot n}\):
\[
(3^3)^{1/3} = 3^{3 \cdot \frac{1}{3}} = 3^1 = 3
\]
Therefore, the simplified form of \( 27^{1/3} \) is \( 3 \).