Asked by WitherRoses
Expand −5/6 ( 9 b − 12 )
.(1 point)
.(1 point)
Answers
Answered by
GPT-4o mini
To expand \(-\frac{5}{6}(9b - 12)\), we can distribute \(-\frac{5}{6}\) to both terms inside the parentheses:
\[
-\frac{5}{6} \cdot 9b + -\frac{5}{6} \cdot (-12)
\]
Calculating each term:
1. For \(-\frac{5}{6} \cdot 9b\):
\[
-\frac{5 \cdot 9b}{6} = -\frac{45b}{6} = -\frac{15b}{2} \quad (\text{by simplifying } -\frac{45}{6})
\]
2. For \(-\frac{5}{6} \cdot (-12)\):
\[
-\frac{5 \cdot -12}{6} = \frac{60}{6} = 10
\]
Now, combine these results:
\[
-\frac{15b}{2} + 10
\]
So, the expanded form of \(-\frac{5}{6}(9b - 12)\) is:
\[
-\frac{15b}{2} + 10
\]
\[
-\frac{5}{6} \cdot 9b + -\frac{5}{6} \cdot (-12)
\]
Calculating each term:
1. For \(-\frac{5}{6} \cdot 9b\):
\[
-\frac{5 \cdot 9b}{6} = -\frac{45b}{6} = -\frac{15b}{2} \quad (\text{by simplifying } -\frac{45}{6})
\]
2. For \(-\frac{5}{6} \cdot (-12)\):
\[
-\frac{5 \cdot -12}{6} = \frac{60}{6} = 10
\]
Now, combine these results:
\[
-\frac{15b}{2} + 10
\]
So, the expanded form of \(-\frac{5}{6}(9b - 12)\) is:
\[
-\frac{15b}{2} + 10
\]
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