Expand −5/6 ( 9 b − 12 )

Question

.(1 point)

Answer 1

To expand \(-\frac{5}{6}(9b - 12)\), we can distribute \(-\frac{5}{6}\) to both terms inside the parentheses:

\[ -\frac{5}{6} \cdot 9b + -\frac{5}{6} \cdot (-12) \]

Calculating each term:

1. For \(-\frac{5}{6} \cdot 9b\): \[ -\frac{5 \cdot 9b}{6} = -\frac{45b}{6} = -\frac{15b}{2} \quad (\text{by simplifying } -\frac{45}{6}) \]

2. For \(-\frac{5}{6} \cdot (-12)\): \[ -\frac{5 \cdot -12}{6} = \frac{60}{6} = 10 \]

Now, combine these results:

\[ -\frac{15b}{2} + 10 \]

So, the expanded form of \(-\frac{5}{6}(9b - 12)\) is:

\[ -\frac{15b}{2} + 10 \]