Asked by keirstan
Add 2n to both sides of the equation to get rid of the −2n on the right, so that all the n terms are on the left side of the equation.
1
5 (12n+8)
10
2
=
−2n+6
12n+8
2
=
−2n+6
6n + 4
=
−2n + 6
+
2n
+
2n
1
5 (12n+8)
10
2
=
−2n+6
12n+8
2
=
−2n+6
6n + 4
=
−2n + 6
+
2n
+
2n
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To add \(2n\) to both sides of the equation, let's start with the original equation:
\[
\frac{1}{5}(12n + 8) = -2n + 6
\]
We can multiply both sides of the equation by 5 to eliminate the fraction:
\[
12n + 8 = 5(-2n + 6)
\]
Now calculating the right side:
\[
12n + 8 = -10n + 30
\]
Now, let's add \(10n\) to both sides to get all the \(n\) terms on the left side:
\[
12n + 10n + 8 = 30
\]
This simplifies to:
\[
22n + 8 = 30
\]
Next, we subtract 8 from both sides:
\[
22n = 22
\]
Now, divide both sides by 22 to solve for \(n\):
\[
n = 1
\]
Now we have solved the equation and found that \(n = 1\). If you need clarification or further steps, feel free to ask!
\[
\frac{1}{5}(12n + 8) = -2n + 6
\]
We can multiply both sides of the equation by 5 to eliminate the fraction:
\[
12n + 8 = 5(-2n + 6)
\]
Now calculating the right side:
\[
12n + 8 = -10n + 30
\]
Now, let's add \(10n\) to both sides to get all the \(n\) terms on the left side:
\[
12n + 10n + 8 = 30
\]
This simplifies to:
\[
22n + 8 = 30
\]
Next, we subtract 8 from both sides:
\[
22n = 22
\]
Now, divide both sides by 22 to solve for \(n\):
\[
n = 1
\]
Now we have solved the equation and found that \(n = 1\). If you need clarification or further steps, feel free to ask!
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