Add 2n to both sides of the equation to get rid of the −2n on the right, so that all the n terms are on the left side of the equation.

Question

1
5 (12n+8)
10
2
=
−2n+6

12n+8
2
=
−2n+6

6n + 4
=
−2n + 6
+
2n
+
2n

Answer 1

To add \(2n\) to both sides of the equation, let's start with the original equation:

\[ \frac{1}{5}(12n + 8) = -2n + 6 \]

We can multiply both sides of the equation by 5 to eliminate the fraction:

\[ 12n + 8 = 5(-2n + 6) \]

Now calculating the right side:

\[ 12n + 8 = -10n + 30 \]

Now, let's add \(10n\) to both sides to get all the \(n\) terms on the left side:

\[ 12n + 10n + 8 = 30 \]

This simplifies to:

\[ 22n + 8 = 30 \]

Next, we subtract 8 from both sides:

\[ 22n = 22 \]

Now, divide both sides by 22 to solve for \(n\):

\[ n = 1 \]

Now we have solved the equation and found that \(n = 1\). If you need clarification or further steps, feel free to ask!