Question
If a car starts at rest and accelerates to 40 m/s in a time of 10 s. What is the acceleration of the car?
\large acceleration=\frac{v_{final}-v_{initial}}{time}
a
-4 m/s2
b
400 m/s2
c
4 m/s
d
4 m/s2
\large acceleration=\frac{v_{final}-v_{initial}}{time}
a
-4 m/s2
b
400 m/s2
c
4 m/s
d
4 m/s2
Answers
GPT-4o mini
To find the acceleration of the car, we can use the formula:
\[
\text{acceleration} = \frac{v_{\text{final}} - v_{\text{initial}}}{\text{time}}
\]
Given:
- \( v_{\text{initial}} = 0 \) m/s (the car starts at rest)
- \( v_{\text{final}} = 40 \) m/s
- \( \text{time} = 10 \) s
Now, plug in the values into the formula:
\[
\text{acceleration} = \frac{40 \, \text{m/s} - 0 \, \text{m/s}}{10 \, \text{s}} = \frac{40 \, \text{m/s}}{10 \, \text{s}} = 4 \, \text{m/s}^2
\]
Thus, the acceleration of the car is:
\[
\text{acceleration} = 4 \, \text{m/s}^2
\]
The correct answer is \( \text{d} \, 4 \, \text{m/s}^2 \).
\[
\text{acceleration} = \frac{v_{\text{final}} - v_{\text{initial}}}{\text{time}}
\]
Given:
- \( v_{\text{initial}} = 0 \) m/s (the car starts at rest)
- \( v_{\text{final}} = 40 \) m/s
- \( \text{time} = 10 \) s
Now, plug in the values into the formula:
\[
\text{acceleration} = \frac{40 \, \text{m/s} - 0 \, \text{m/s}}{10 \, \text{s}} = \frac{40 \, \text{m/s}}{10 \, \text{s}} = 4 \, \text{m/s}^2
\]
Thus, the acceleration of the car is:
\[
\text{acceleration} = 4 \, \text{m/s}^2
\]
The correct answer is \( \text{d} \, 4 \, \text{m/s}^2 \).