Identify the vertex of y=4(x−25)^2−61 .(1 point) Responses (−100,−61) left parenthesis negative 100 comma negative 61 right parenthesis (25,−61) left parenthesis 25 comma negative 61 right parenthesis (4,−25) left parenthesis 4 comma negative 25 right parenthesis (−25,−61)

Answer 1

In the given equation \( y = 4(x - 25)^2 - 61 \), we can identify the vertex by recognizing that it is in the vertex form of a quadratic equation, which is \( y = a(x - h)^2 + k \), where \((h, k)\) represents the vertex.

From the equation:

• \( h = 25 \)
• \( k = -61 \)

Thus, the vertex is \((25, -61)\).

The correct response is \((25, -61)\).