To find the zeros of the quadratic function \( y = -5x^2 + 16x \), we can set the equation equal to zero and solve for \( x \):
\[ -5x^2 + 16x = 0 \]
Next, we can factor out the common term \( x \):
\[ x(-5x + 16) = 0 \]
This equation will equal zero if either \( x = 0 \) or \( -5x + 16 = 0 \).
- From \( x = 0 \), we have one zero at \( (0, 0) \).
- Now, let's solve \( -5x + 16 = 0 \):
\[ -5x + 16 = 0 \ 5x = 16 \ x = \frac{16}{5} = 3.2 \]
This gives us another zero at \( (3.2, 0) \).
Thus, the zeros of the function \( y = -5x^2 + 16x \) are \( (0, 0) \) and \( (3.2, 0) \).
The correct response from the given options is:
(3.2, 0).