3(8h+24)

12
=
−3h+21

Divide the numerator and the denominator by 3

Multiply the numerator by 3

Divide the numerator by 21

1 answer

It seems like you're expressing some algebraic manipulation steps, but the operations need clarification. Let's break down your initial expression and apply the operations you've mentioned step by step.

Starting from your initial expression:

\[ 3(8h + 24) \]

  1. Expand the expression: \[ 3(8h + 24) = 24h + 72 \]

Now let's address the options you provided.

  1. Divide the numerator and the denominator by 3: Assuming you are referring to \((24h + 72)/12\): \[ \frac{24h + 72}{12} = \frac{24h}{12} + \frac{72}{12} = 2h + 6 \]

  2. Multiply the numerator by 3: You can take the previous result \((24h + 72)/12\) and multiply the numerator: \[ \frac{3(24h + 72)}{12} = \frac{72h + 216}{12} = 6h + 18 \]

  3. Divide the numerator by 21: If we take \(24h + 72\) and divide by 21, we would get: \[ \frac{24h + 72}{21} = \frac{24h}{21} + \frac{72}{21} = \frac{8h}{7} + \frac{24}{7} \]

To clarify further, if you have a specific expression or context for these operations, please provide that, and I can give you a more focused answer or expression manipulation.