To solve the factored quadratic equation \( (19x - 3)(9 + x) = 0 \), we can set each factor equal to zero.
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Set the first factor equal to zero: \[ 19x - 3 = 0 \] Solving for \( x \): \[ 19x = 3 \implies x = \frac{3}{19} \]
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Set the second factor equal to zero: \[ 9 + x = 0 \] Solving for \( x \): \[ x = -9 \]
Thus, the solutions are: \[ x = -9 \quad \text{and} \quad x = \frac{3}{19} \]
The solution set is: \[ { -9, \frac{3}{19} } \]
The correct response is: The solution set is \( x = { -9, \frac{3}{19} } \).